05-21 18657人
- 用一个不报毒的域名,放入一下代码(PHP)!
- 原理就是 利用不报毒域名打开+QQ跳转浏览器 + 跳转到主域名
- 测试系统:ios、测试域名:cn、top 测试结果:OK
//直接跳转到指定网址
<?php $url = "http://www.qzoner.cn";//这里是要跳转的域名 $scriptpath = str_replace('\\', '/', $_SERVER['SCRIPT_NAME']); $sitepath = substr($scriptpath, 0, strrpos($scriptpath, '/')); $siteurl = ($_SERVER['SERVER_PORT'] == '443' ? 'https://' : 'http://') . $_SERVER['HTTP_HOST'] . $sitepath . '/'; if (strpos($_SERVER['HTTP_USER_AGENT'], 'QQ/') !== !1 ) { echo '<!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>请使用浏览器打开</title> <script src="https://open.mobile.qq.com/sdk/qqapi.js?_bid=152"></script> <script type="text/javascript"> mqq.ui.openUrl({ target: 2,url: "' . $url . '"}); </script> </head> <body></body> </html>'; exit; }else{ echo "<script type='text/javascript'>"; echo "window.location.href='$url'"; echo "</script>"; } ?>
//先用浏览器打开当前域名 再做跳转
<?php $url = "http://www.qzoner.cn";//这里是要跳转的域名 $scriptpath = str_replace('\\', '/', $_SERVER['SCRIPT_NAME']); $sitepath = substr($scriptpath, 0, strrpos($scriptpath, '/')); $siteurl = ($_SERVER['SERVER_PORT'] == '443' ? 'https://' : 'http://') . $_SERVER['HTTP_HOST'] . $sitepath . '/'; if (strpos($_SERVER['HTTP_USER_AGENT'], 'QQ/') !== !1 ) { echo '<!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>请使用浏览器打开</title> <script src="https://open.mobile.qq.com/sdk/qqapi.js?_bid=152"></script> <script type="text/javascript"> mqq.ui.openUrl({ target: 2,url: "' . $siteurl. '"}); </script> </head> <body></body> </html>'; exit; } echo "<script type='text/javascript'>"; echo "window.location.href='$url'"; echo "</script>"; ?>
top域名不能用?
谢谢
怎么用啊
不行,,不知道是我不会,还是代码问题。
怎么用